Given an array with numerical values, the largest element can be found in multiple ways.
We can use solve this problem in the following ways in Python:
for-in loopmax()sort()for-in loopfor-in loop and a variable that stores the largest element to solve this.lst with [20, 49, 1, 99].largest variable with the first element in the list.for-in loop to traverse every element in the list, and check if the current element i is greater than the value present in the largest variable.i to the variable largest.largest will store the largest element in the list.#initialize listlst = [20, 49, 1, 99]#initialize largest with first elementlargest = lst[0]#traverse the arrayfor i in lst:if i>largest:largest = iprint(largest)
max()We will use Python’s built-in function max() to solve this problem.
lst as a parameter to the function max(), which returns the largest element in the list.#initialize listlst = [20, 49, 1, 99]#returns largest elementlargest = max(lst)#print largest in the listprint(largest)
sort()We will use the sort() method to solve this.
lst with [20, 99, 1, 49].lst with lst.sort(), which sorts the original list in ascending order.lst[-1] in the list is the largest. Print it.#initialize listlst = [20, 99, 1, 49]#sort the listlst.sort()#print last element which is largestprint(lst[-1])