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Advanced TypeScript Masterclass

The `infer` Keyword

Explore the infer keyword in TypeScript to extract parameter and return types from functions using conditional types. Understand how to apply this for advanced type manipulation and better compile-time error checking.

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Parameters

The Parameters type takes a function type and returns a tuple type representing types of all parameters of the function. Sounds magical, doesn’t it?

TypeScript 3.3.4
type Parameters<T extends (...args: any) => any> = T extends (...args: infer P) => any ? P : never;
const sayHello = (name: string, age: number) => `Hello ${name}, your age is ${age}`;
type SayHelloParams = Parameters<typeof sayHello>; // [string, number]

Let’s break down this definition. First, the Parameters type has a type argument constraint that says that T must be a function type ((...args: any) => any). Next, inside the conditional expression we say that T extends (...args: infer P) => any. ...