Counting-Based Sorting
Learn about counting-based sorting algorithms.
In this lesson we’ll learn about two sorting algorithms that are not comparison-based. Specialized for sorting small integers, these algorithms elude the lower-bounds of Theorem 1 in previous lesson by using (parts of) the elements in a as indices into an array. Consider a statement of the form
This statement executes in constant time, but has c.length
possible different outcomes, depending on the value of a[i]
. This means that the execution of an algorithm that makes such a statement cannot be modeled as a binary tree. Ultimately, this is the reason that the algorithms in this section are able to sort faster than comparison-based algorithms.
Counting-sort
Suppose we have an input array consisting of integers, each in the
range . The counting-sort algorithm sorts using an auxiliary
array c
of counters. It outputs a sorted version of a
as an auxiliary array
The idea behind counting-sort is simple: For each , count the number of occurrences of i
in a and store this in c[i]
. Now, after sorting, the output will look like c[0]
occurrences of 0
, followed by
c[1]
occurrences of 1
, followed by c[2]
occurrences of followed by c[k − 1]
occurrences of k − 1
.
Visual demonstration of counting-sort
The code that does this is very slick, and its execution is illustrated below:
The implementation of counting_sort()
is:
def counting_sort(a, k):c = new_zero_array(k)for i in range(len(a)):c[a[i]] += 1for i in range(1, k):c[i] += c[i-1]b = new_array(len(a))for i in range(len(a)-1, -1, -1):c[a[i]] -= 1b[c[a[i]]] = a[i]return b
Counting-sort analysis
The first for
loop in this code sets each counter c[i]
so that it counts
the number of occurrences of i
in a
. By using the values of a
as indices, these counters can all be computed in ...