Angle Between the Hands of a Clock
Understand and solve the interview question "Angle Between the Hands of a Clock."
We'll cover the following...
Description
Given two numbers, hour
and minutes
we will return the smaller angle (in degrees) formed between the hour
and the minute
hands on a clock.
Let’s look at some examples to better understand this:
Coding exercise
import Swiftfunc clockAngle(hour: Int, minutes: Int) -> Float64 {// Your code goes herereturn 0.1 // Change the return value as per your requirement}
Solution
The idea is to separately calculate the angles between the 0-minutes vertical line and each hand. The answer will be the difference that is found between the two angles.
Note: Black lines in the clock represent the 0-minutes vertical lines.
Minute hand angle
Let’s start from the minute hand. The minute hand moves with 1 min
intervals. At 1 min
, the angle of the minute hand is 6°
. . Since the whole circle of the clock is equal to 360°
degrees and 60
minutes, we estimated that the minute hand moves 1 min = 360° / 60 = 6°
degree with each minute.
Now, we can easily find an angle between the 0-minutes vertical line and a minute hand, using minutesAngle = minutes X 6°
. ...