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Solution: Flow Lifecycle Functions

Solution: Flow Lifecycle Functions

See the solution to the challenge just presented.

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Solution

The solution to the challenge we just solved is as follows.

suspend fun main() {
    flowOf("A", "B")
        .onEach { delay(2000) }
        .onStart { println("Started") }
        .collect { println(it) }
}
Complete code of the solution

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