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/Feature #15: Queue Reconstruction by Priority
Feature #15: Queue Reconstruction by Priority
Implement the "Queue Reconstruction by Priority" feature for our "Operating System" project.
We'll cover the following...
Description
A process queue contains the process priority. It also contains the number of processes ahead of a process in the queue that has a priority not less than its own. Suppose that the OS crashed and now we only have an array of processes, with each process at a random position in the array. In this feature, we’ll reconstruct the process queue from the information available to us.
Each element in the 2D array consists of a process’s priority and the number of processes with a higher or equal priority that are ahead of it in the queue. An entry [pi, ki]
represents that a process with priority pi
has ki
other processes, with a priority of at least pi
, ahead of it in the queue
.
Our task is to reconstruct and return the process queue.
Let’s look at a few examples of this:
Solution
A process with a lower priority does not affect the placement of k
processes with a higher priority. So, we will first insert the processes with a higher priority, into the output array. We will start by sorting the input array in descending order of process priority, and then in ascending order of the k-value. We will:
- Sort the processes by priority, in a descending order.
- Sort the processes with the same priority in ascending order of
k
.
We will pick elements from the sorted array, starting at index 0. If the element picked is [pi, ki]
, it will be inserted at index k
in the output array. The following slides demonstrate this procedure:
Let’s take a look at an example of this:
std::vector<std::vector<int>> reconstructQueue(std::vector<std::vector<int>>& process) {std::vector<std::pair<int, int>> temp;std::vector<std::pair<int, int>> temp2(process.size());for (int k = 0; k < process.size(); k++){temp.push_back({process[k][0], process[k][1]});}// First sort processes by priority and then by the k value.// priority in descending order and k value in ascending order.std::sort(temp.begin(), temp.end(), [](std::pair<int, int> p1, std::pair<int, int> p2){return p1.first > p2.first || (p1.first == p2.first && p1.second < p2.second);});for (int i = 0; i < temp.size(); i++){temp2.insert(temp2.begin() + temp[i].second, temp[i]);}// Place the result back in original 2d arrayfor (int l = 0; l < process.size(); l++){process[l][0] = temp2[l].first;process[l][1] = temp2[l].second;}return process;}int main() {// Driver Codestd::vector<std::vector<int>> p = {{7, 0}, {4, 4}, {7, 1}, {5, 0}, {6, 1}, {5, 2}};auto sol = reconstructQueue(p);print(sol);return 0;}