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Feature #15: Queue Reconstruction by Priority

Feature #15: Queue Reconstruction by Priority

Implement the "Queue Reconstruction by Priority" feature for our "Operating System" project.

Description

A process queue contains the process priority. It also contains the number of processes ahead of a process in the queue that has a priority not less than its own. Suppose that the OS crashed and now we only have an array of processes, with each process at a random position in the array. In this feature, we’ll reconstruct the process queue from the information available to us.

Each element in the 2D array consists of a process’s priority and the number of processes with a higher or equal priority that are ahead of it in the queue. An entry [pi, ki] represents that a process with priority pi has ki other processes, with a priority of at least pi, ahead of it in the queue.

Our task is to reconstruct and return the process queue.

Let’s look at a few examples of this:

Solution

A process with a lower priority does not affect the placement of k processes with a higher priority. So, we will first insert the processes with a higher priority, into the output array. We will start by sorting the input array in descending order of process priority, and then in ascending order of the k-value. We will:

  • Sort the processes by priority, in a descending order.
  • Sort the processes with the same priority in ascending order of k.

We will pick elements from the sorted array, starting at index 0. If the element picked is [pi, ki], it will be inserted at index k in the output array. The following slides demonstrate this procedure:

Let’s take a look at an example of this:

function reconstructQueue(process) {
var temp = [];
var temp2 = [];
for (var k = 0; k < process.length; k++)
{
temp.push([process[k][0], process[k][1]]);
}
// First sort processes by priority and then by the k value.
// priority in descending order and k value in ascending order.
temp.sort((x, y) => {
return x[0] < y[0] || (x[0] == y[0] && x[1] > y[1])
});
for (var p of temp) {
temp2.splice(p[1], 0, p);
}
return temp2;
}
var p = [[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]];
var sol = reconstructQueue(p);
console.log(sol)
Queue reconstruction by priority
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