Solution: Continuous Subarray Sum
Let's solve the Continuous Subarray Sum problem using the hash maps pattern.
We'll cover the following
Statement
Given an integer array nums
and an integer k
, determine if nums
contains a good subarray. Return true
if such a subarray exists; otherwise, return false
.
A subarray of nums
is considered good if:
Its length is at least
. The sum of its elements is a multiple of
k
.
Notes:
A subarray is defined as a contiguous sequence of elements within an array.
An integer
x
is a multiple ofk
if there exists an integern
such thatx = n * k
. Note that0
is always considered a multiple ofk
.
Constraints:
nums.length
nums[i]
sum(nums[i])
k
Solution
This algorithm’s essence is identifying a subarray in nums
whose sum is a multiple of k
. We accomplish this by using cumulative sums and their remainders when divided by k
. A hash map helps us quickly check if a particular remainder has been encountered before, allowing us to detect subarrays with the desired property.
Here’s why remainders are essential: when we divide a cumulative sum by k
, the remainder reveals the part that isn’t divisible by k
. If two cumulative sums yield the same remainder when divided by k
, then the difference between these cumulative sums is divisible by k
. This indicates that the subarray between these two indices has a sum that’s a multiple of k
.
For instance, if we have cumulative sums at indices i
and j
where i
matches the remainder at index j
, then:
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