It seems like coding interviews are only getting harder, and preparing for them isn’t an easy task. There’s no limit to the kind of questions that may be presented to you in an interview, and many of them aren’t easy. The “hardest” questions will be different for each person. What comes easily to you may be extremely difficult for someone else, and vice versa.
No matter what your “hardest” questions are, it’s crucial focus on your tech interview prep. We talked to junior and senior developers for their take on the hardest coding interview questions, and we compiled the top five into a list. Today, we’ll explore that list in more detail and give you some tips on how to prepare.
If you’ve never heard of it, the garbage collector problem is known to be very difficult. Garbage collection is a topic that most people don’t learn about in school, and the related material is extremely dense. Learning about garbage collection involves a lot of theory, which can be overwhelming. No matter what language you work in, it’s crucial to know the ins and outs of your preferred language to solve this problem effectively.
Don’t be afraid to ask your interviewer questions as you work through this problem. Remember that your interviewer is there to help you and wants to see you do well. It’s common for interviewers to give you little seeds of information to help push you in the right direction.
Note: Garbage collection questions are especially common in core and advanced Java interviews, but they are also important to know for other programming languages.
The coin change problem is commonly seen at Facebook and Amazon interviews. You’re given coins of different denominations and a total amount of money. From that, you need to write a function to compute the fewest number of coins that you need to make up that amount. If you can’t reach the given amount of money with any combination of the coins, you return -1.
Here are three ways you could solve this problem:
Let’s take a look at the bottom-up dynamic programming with tabularization solution in C++:
#include <iostream>using namespace std;int countChange(int denoms[], int denomsLength, int amount) {// Edge casesif(amount <= 0 || denomsLength <= 0)return 0;int i, j, x, y;// We need n+1 rows as the table// is constructed in bottom up// manner using the base case 0// value case (n = 0)int lookupTable[amount + 1][denomsLength];// Fill the enteries for 0// value case (n = 0)for (i = 0; i < denomsLength; i++)lookupTable[0][i] = 1;// Fill rest of the table entries// in bottom up mannerfor (i = 1; i < amount + 1; i++) {for (j = 0; j < denomsLength; j++) {// Count of solutions including denoms[j]x = (i - denoms[j] >= 0) ? lookupTable[i - denoms[j]][j] : 0;// Count of solutions excluding denoms[j]y = (j >= 1) ? lookupTable[i][j - 1] : 0;// total countlookupTable[i][j] = x + y;}}return lookupTable[amount][denomsLength - 1];}// Driver Codeint main() {int denoms[4] = {25,10,5,1};cout << countChange(denoms, 4, 10) << endl;}
For each iteration of the inner loop, we get the solution with denoms[j] and store it in x. We also get the solution without denoms[j] and store it in y. By doing this, we’re able to reference earlier solutions to avoid duplicate computations.
For each coin in the denomination, there can only be two possibilities: to include it or exclude it. We know that if the coin, denom[j], is larger than amount, then x is set to 0 since including it into consideration is impossible.
The time complexity is , which is the number of for loop iterations.
Note: Each of these three methods includes time complexity, meaning that time complexity is an important concept to understand to succeed at the coin change problem.
The dining philosophers problem is commonly used in concurrent algorithm design to demonstrate issues with synchronization and the techniques to solve them. The problem states that there are five philosophers sitting around a circular table. The philosophers must alternatively think and eat.
Each philosopher has a bowl of food in front of them, and they require a fork in each hand to eat. However, there are only five forks available. You need to design a solution where each philosopher can eat their food without causing a deadlock.
With this problem, it’s common for developers to overlook the idea that it’s not really asking about a real-world scenario, but rather illustrating the kinds of problems you could run into in threaded program executions and/or negligent handling of locks. The idea is to get you to think about limitations and proper ordering to accomplish this task in the most efficient way.
To prepare for this question, you should dive deeper into synchronization, concurrency control, and semaphores.
Here are two possible ways to solve this problem:
Let’s look at the reordering the fork pick-up solution in Java:
public class DiningPhilosophers2 {private static Random random = new Random(System.currentTimeMillis());private Semaphore[] forks = new Semaphore[5];public DiningPhilosophers2() {forks[0] = new Semaphore(1);forks[1] = new Semaphore(1);forks[2] = new Semaphore(1);forks[3] = new Semaphore(1);forks[4] = new Semaphore(1);}public void lifecycleOfPhilosopher(int id) throws InterruptedException {while (true) {contemplate();eat(id);}}void contemplate() throws InterruptedException {Thread.sleep(random.nextInt(500));}void eat(int id) throws InterruptedException {// We randomly selected the philosopher with// id 3 as left-handed. All others must be// right-handed to avoid a deadlock.if (id == 3) {acquireForkLeftHanded(3);} else {acquireForkForRightHanded(id);}System.out.println("Philosopher " + id + " is eating");forks[id].release();forks[(id + 1) % 5].release();}void acquireForkForRightHanded(int id) throws InterruptedException {forks[id].acquire();forks[(id + 1) % 5].acquire();}// Left-handed philosopher picks the left fork first and then// the right one.void acquireForkLeftHanded(int id) throws InterruptedException {forks[(id + 1) % 5].acquire();forks[id].acquire();}}
In this solution, you make any one of the philosophers pick up the left fork first instead of the right one. It doesn’t matter which philosopher you choose to be left-handed and made to pick up their left fork first. In our solution, we chose the philosopher with id=3 as our left-handed philosopher.
Keep the learning going.#
Stop grinding through endless practice questions, and start breaking down relevant problems into recognizable patterns.
Educative’s curated coding interview prep courses are easy to skim and feature hands-on coding environments and real-world examples to help you interview with confidence.
Answer any interview problem by learning the patterns behind common questions.#
While learning about programming, you typically learn some “best practices.” The most efficient developers implement certain practices into their coding process, which helps them ensure that their code is the best it can be in both function and form.
After years of experience with programming, you tend to know the practices you should avoid and the ones you should adopt. You may have a general idea of why some practices are better than others, but stumble when it’s time to explain the reasoning.
A few examples of best practices include:
The best way to prepare yourself for these questions is to refresh your memory on useful versus avoidable practices and the reasoning behind them. Remember that during your interview, you can talk through these questions with your interviewer.
The Least Recently Used (LRU) cache implementation question is asked in some Google, Microsoft, and Amazon interviews, but it’s not a very common question. This question requires you to think deeper and combine two or more existing data structures.
It’s important to read the problem slowly and make sure you understand what’s being asked of you. These questions typically ask you to do a few things. Once you’ve read the problem thoroughly, you can ask your interviewer to confirm that you’re going in the right direction.
Before tackling one of these problems, make sure you understand what cache is. LRU is a common caching strategy that defines the policy to remove elements from the cache to make room for new ones when the cache is full. This means that it discards the least recently used items first.
Be confident in any coding interview#
Start preparing for your coding interview today. Educative’s coding interview prep is available in five programming languages: Python, Java, C++, JavaScript, and Go.
You’ll learn to recognize common coding patterns used at top tech companies such as Google, Microsoft, Amazon, and Facebook. By the end, you’ll be prepared to interview with confidence.
The questions we covered today are just a few of the many difficult coding interview questions. The questions are supposed to be difficult, and they can even stump the most seasoned developers. It’s important to begin your interview prep early, so you have the opportunity to prepare as much as possible. A few more difficult problems include:
Begin preparing for your coding interview today with Educative’s Grokking Coding Interview Patterns series.
Our team of experts has incorporated the most commonly asked interview questions at top tech companies into a carefully crafted set of scenarios for you to learn from. You can practice as you learn with hands-on coding environments directly inside your browser. Our coding interview course has helped developers prepare for interviews with top tech companies like Netflix, Facebook, Microsoft, Amazon, and Google.
By the end, you’ll be ready to interview with confidence!
Happy learning!
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