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Solution: LCM of Multiple Numbers Using a Method

Solution: LCM of Multiple Numbers Using a Method

Go over the implementation of finding the LCM of a range of numbers with a method in Ruby.

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Solution

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def lcm(a, b)
	(a..a*b).each do |n|
		if n % a == 0 && n % b == 0
			return n
		end # end of if
	end # end of loop
end # end of method
m = 1
(2..15).each do |w|
	m = lcm(m, w)
end
puts "The lowest number that is dividable by 1 to 15 is: #{m}"
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