Solution: Linked List Cycle III
Let’s solve the Linked List Cycle III problem using the Fast and Slow Pointers pattern.
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Statement
Given the head of a linked list, determine the length of the cycle present in the linked list. If there is no cycle, return 0.
A cycle exists in a linked list if there is some node in the list that can be reached again by continuously following the next pointer.
Constraints:
The number of nodes in the list is in the range
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