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Solution Review 2: Count Iterations of a Loop Until a Condition

Solution Review 2: Count Iterations of a Loop Until a Condition

This lesson gives a detailed solution review of the challenge in the previous lesson.

We'll cover the following...

Solution:

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fn test(mut x:i32) {
// define a mutable variable
let mut count = 0;
// define a while loop
while x >= 0 {
x = x - 3; // decrement the value of x by 3
count = count + 1;
}
println!("{}", count);
}
fn main(){
print!("Iterations when x = 21 :");
test(21);
print!("Iterations when x = 33 :");
test(33);
}
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