Problem Solving: Students Grading Calculator

Students grader

Take the record of k students (where each record consists of five courses, marked out of 100) and display their achieved total marks and grades side by side. After displaying the last (k$^{th}$ record), it should also display which students have the highest percentage and grade.

Here is the grading scheme that our program must follow:

Implementation

We will make the grader by solving the following functions as units and, after testing every unit, integrate them all into the required program.

Sample output

k = 3

Student 1(Roll# C1 C2 C3 C4 C5) : 1111 88 99 99 100 97
Compiled Result: Roll# 1111 has a percentage of 96.6% and achieved grade A

Student 2(Roll# C1 C2 C3 C4 C5) : 1112 90 78 56 89 90
Compiled Result: Roll# 1112 has a percentage of 80.6% and achieved a grade B

Student 3(Roll# C1 C2 C3 C4 C5) : 1113 88 44 55 66 77
Compiled Result: Roll# 1113 has a percentage of 80.6% and achieved a grade C

Roll# 1111 has the highest percentage of 96.6% and achieved grade A

Let’s divide this problem into two parts. The first part will follow the grading scheme and the second part will compile the result. We have the following division:

1. The marksGrader() function takes marks and returns the grade according to the grading scheme.
2. The kStudentsResult() function is a core function that will perform the compilation task of the k student records.

Let us discuss the marksGrader() function first:

1. The marksGrader() function

This function should take the percentage of a student and print the corresponding letter grade.

Sample input

92

Sample output

A

We can easily see from our problem that we need a function marksGrader() that takes an integer as input and returns a character (the letter grade). Hence the prototype should be:

char marksGrader(int marks);

Now, this function will take the parameter marks and return the corresponding letter grade instead of printing it on the console. This is a significant change that we are adopting in the entire chapter of this course. We should ponder why we are doing this. The reason is, again, that this grader is now a separate module that we can call from anywhere and use its result to do several tasks.

We can implement the marksGrader() function in three different ways:

Let’s test this code with the appropriate main():

• In lines 13–29, we compare each percentage range with marks and return letter grades accordingly. For example, if marks are 86, it will return 'B'.

Let’s move to the next function.

2. The kStudentsResult() function

We will make a function kStudentsResult(), in which we will pass k as an argument. This is the core function, which will perform the compilation task of the k records.

As per our requirements, we will make the following memory variables.

Inside the function, we will make a loop that will take the input of k students’ course marks together with their roll numbers in each iteration. We will pass the marks to a percentageCourses() function to calculate the percentage of each student. But there is a question for you: how will we keep the roll number of the student with the highest percentage?

In the previous lesson, we discussed the functionality of the maximum number. How can we use that functionality to solve this problem? We initially assign -1 to max_percentage. In each iteration of the for loop, we will take a student’s record and calculate the percentage. If the current student’s percentage is greater than the max_percentage, then we will replace max_percentage with the current student’s percentage. We will also update max_r_no with the current student’s roll number.

Let’s see how to write what we’ve discussed above in a function:

Let’s write a complete code below and see the output: