Solution: Count Element Occurrence
Here is a detailed analysis of the different ways to count the frequency of a number in a sorted array of integers
Solution #1: Brute Force with Linear Search
Press + to interact
#include <iostream>using namespace std;int calcFreq(int arr[], int arrSize, int s) {int count = 0;for(int i = 0; i < arrSize; i++) {if(arr[i] == s)count++;}return count;}int main() {int arr[] = {-5,-3,0,1,3,3,3,3,4,5};cout << calcFreq(arr, 10, 3) << endl;}
This is an extremely simple way to solve this problem. We simply initialize a variable to keep count called, count
to 0 and then iterate over the array, increasing count
by 1 every time the target value is encountered.
Time Complexity
The time complexity of this algorithm is in ...
Access this course and 1400+ top-rated courses and projects.