Solution Review: Min Stack
Let's discuss the solution of the challenge posed in the previous lesson.
We'll cover the following...
Solution: A two-stack class
Weāll make a new class consisting of two stacks: mainStack
and minimumStack
. The class will have the following functions:
Push()
Pop()
Min()
Letās see what each function will do:
-
Push
: Push an element to the top ofmainStack
. It compares the new value with the value at the top ofminimumStack
. If the new value is smaller, ...