Gain insights into using Modern C++ for embedded programming. Learn about safety-critical systems, optimize performance, manage limited resources, and handle parallel execution effectively.

waleed1.tar.gz

C++11

C++ 17

Embedded Programming with Modern C++  is highly valuable for each professional programmer.

In the past, embedded and system programming have had their pitfalls, but modern C++ has been designed to be a better language for this type of development, addressing the previous pitfalls/requirements explicitly. What are these requirements? Embedded systems deal with safety-critical systems, meaning they must guarantee high performance combined with limited resources, while also working in parallel.

The scope of this course goes beyond just embedded programming. Developers who write servers, games, or trading systems may especially benefit from this course because they also have to deal with safety-critical systems, high performance, reduced resources, and parallel execution in their jobs.

To get the most out of the course, you only need a basic understanding of C++. Building off this understanding, this course goes over all the essentials of embedded programming with Modern C++.

Let's get started!

Embedded Programming with Modern C++

// staticAssertGcd.cpp

#include <iostream>
#include <type_traits>

template<typename T>
T gcd(T a, T b){
  static_assert(std::is_integral<T>::value, "T should be an integral type!");
  if( b == 0 ){ return a; }
  else{
    return gcd(b, a % b);
  }
}

int main(){

  std::cout << std::endl;

  std::cout << gcd(3.5, 4.0)<< std::endl; // should be gcd(3, 4)
  std::cout << gcd("100", "10") << std::endl; // should be gcd(100, 10)

  std::cout << std::endl;

}

## Explanation

The `static_assert` operator and the predicate `std::is_integral<T>::value` enable us to check at compile time whether or not `T` is an integral type. A predicate always returns a `boolean` value. 

The compilation will not fail by accident since the modulo operator is not defined for a `double` value and a C string, but the compilation fails since the assertion in line 8 will not hold true. Now, we get an exact error message rather than a cryptic output of a failed template instantiation.


> The rule is quite simple: **If a compilation must fail, we will get an unambiguous error message.
**




In this lesson, we will look at the solution to using assertations to ensure that the algorithm only accepts natural numbers.

Introduction

Safety-Critical Systems

High Performance

Reduced Resources

Several Tasks Simultaneously

Conclusion

- Solution