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Solution Review: Balance Parenthesis

Solution Review: Balance Parenthesis

This review provides a detailed analysis of the solution to determine whether or not an array contains balanced parenthesis.

Solution: Using Recursion

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def balanced(testVariable, startIndex = 0, currentIndex = 0) :
# Base case1 and 2
if startIndex == len(testVariable) :
return currentIndex == 0
# Base case3
if currentIndex < 0 : # A closing bracket did not find its corresponding opening bracket
return False
# Recursive case1
if testVariable[startIndex] == "(" :
return balanced(testVariable, startIndex + 1, currentIndex + 1)
# Recursive case2
elif testVariable[startIndex] == ")" :
return balanced(testVariable, startIndex + 1, currentIndex - 1)
# Driver Code
testVariable = ["(", "(", ")", ")", "(", ")"]
print(balanced(testVariable))

Explanation

Our task is to read an array of parentheses from left to right and decide whether the symbols are balanced.

To solve this problem, notice that the most recent opening ...

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