Solution: Skiplists
See the solution that modifies the find(x) method in a skiplist.
We'll cover the following...
Problem
This task implements the find(x)
method in a SkiplistSSet
and sometimes performs redundant comparisons; these occur when x
is compared to the same value more than once. They can occur when, for some node, u
, u.next[r] = u.next[r − 1]
. Modify the find(x)
so that these redundant comparisons are avoided.
Solution
The findPredNode(T x)
method in the SkiplistSSet
class is a helper ...
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