Solution: Unique Number of Occurrences
Let's solve the Unique Number of Occurrences problem using the Hash Maps pattern.
We'll cover the following...
Statement
Given an array of integers nums
, return TRUE if each value in the array has a unique number of occurrences; otherwise, return FALSE.
Constraints:
<= nums.length
<=<= nums[i]
<=
Solution
The algorithm checks if there is a unique number of occurrences of each element by using a hash map and a hash set. First, for each element of the nums
array, put the element in the hash map if it does not already exist in the hash map; otherwise, increment its count. Second, put all the elements' frequencies (counts) in a hash set. Finally, the algorithm will return TRUE if the count of the hash map and the hash set is the same and FALSE otherwise.
The algorithm to solve this problem ...