Solution Review: Filtering with Higher-Order Functions

This lesson discusses the solution to the challenge given in the previous lesson.

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package main
import (
"fmt"
)
func main() {
s := []int{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
s = Filter(s, even)
fmt.Println(s)
}
// Filter returns a new slice holding only
// the elements of s that satisfy fn()
func Filter(s []int, fn func(int) bool) []int {
var p []int // == nil
for _, i := range s {
if fn(i) {
p = append(p, i)
}
}
return p
}
func even(n int) bool {
if n%2 == 0 {
return true
}
return false
}

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